2WAP

Answer this question pls

22 replies 215 views
Newest ↓
Eternal_Knight OP
15 years ago
I request 2wap scholars on physics to solve this question n help me for answer. The question is based on gravitation chapter of 12th standard[MAHARASHTRA,INDIA ]:*... Thank you
Eternal_Knight OP
15 years ago
#1
The question is find the height of communication satellite.[given G=6.67*10raise to -11,Mas of earth=6*10raise to 24kg,radius of earth=6400km ]. Be kind enuf to attach the page on which u have solved. Or explain here. Thank you
Insenus_AmoR
15 years ago
#10
For the communication satellite, T=24 hours = 86400sec. G and M are given, Substituting these values in the formula, we get r^3=(T^2 * G * M)/ 4*pi^2 (86400^2) x6.67x10^-11 x 6 x 10^24/(4*(3.14^2)) r^3 = 7.542*10^22 r=42.25 *10^6 m If h is the height of the satellite above the surface of the earth and R is the radius of the earth, r = R + h h = r-R Now R = 6400 km = 6.4 x 10^6 m h =r-R = 42.25 x 10^6 - 6.4x10^6 = 35.85 x 106 m = 35850 kms smiley
EpIcInCoGnItO
15 years ago
#11
smiley whats the hell?
AfaQue: For the communication satellite, T=24 hours = 86400sec. G and M are given, Substituting these values in the formula, we get r^3=(T^2 * G * M)/ 4*pi^2 (86400^2) x6.67x10^-11 x 6 x 10^24/(4*(3.14^2)) r^3 = 7.542*10^22 r=42.25 *10^6 m If h is the height of the satellite above the surface of the earth and R is the radius of the earth, r = R + h h = r-R Now R = 6400 km = 6.4 x 10^6 m h =r-R = 42.25 x 10^6 - 6.4x10^6 = 35.85 x 106 m = 35850 kms smiley
Share WhatsApp Telegram SMS

Log in or join to reply.