Answer this question pls

Eternal_Knight

2011/01/10 13:45

The question is find the height of communication satellite.[given G=6.67*10raise to -11,Mas of earth=6*10raise to 24kg,radius of earth=6400km ]. Be kind enuf to attach the page on which u have solved. Or explain here. Thank you

Dunrichie

2011/01/10 13:59

Oops...... I'm not a science student.

Elfuego

2011/01/10 13:59

Y u wnt d answa 2 datÂ¿?

_GUL_

2011/01/10 14:06

I am n0t fr0m them' smiley

STAIN

2011/01/10 14:24

Sorry am not a Science student.

Laketempest

2011/01/10 14:24

okay bro lol

Eternal_Knight

2011/01/10 15:06

Where is enrique? ? ? ? ?

R49hu

2011/01/10 16:42

i donno i am afraid of mathenatical solutions

Samuel

2011/01/14 07:49

God wil prvd d answ

Insenus_AmoR

2011/01/16 19:36

For the communication satellite, T=24 hours = 86400sec. G and M are given, Substituting these values in the formula, we get r^3=(T^2 * G * M)/ 4*pi^2 (86400^2) x6.67x10^-11 x 6 x 10^24/(4*(3.14^2)) r^3 = 7.542*10^22 r=42.25 *10^6 m If h is the height of the satellite above the surface of the earth and R is the radius of the earth, r = R + h h = r-R Now R = 6400 km = 6.4 x 10^6 m h =r-R = 42.25 x 10^6 - 6.4x10^6 = 35.85 x 106 m = 35850 kms smiley

EpIcInCoGnItO

2011/01/16 19:42

whats the hell?

AfaQue: For the communication satellite, T=24 hours = 86400sec. G and M are given, Substituting these values in the formula, we get r^3=(T^2 * G * M)/ 4*pi^2 (86400^2) x6.67x10^-11 x 6 x 10^24/(4*(3.14^2)) r^3 = 7.542*10^22 r=42.25 *10^6 m If h is the height of the satellite above the surface of the earth and R is the radius of the earth, r = R + h h = r-R Now R = 6400 km = 6.4 x 10^6 m h =r-R = 42.25 x 10^6 - 6.4x10^6 = 35.85 x 106 m = 35850 kms smiley