Answer this question pls by Eternal_Knight 2011/01/10 13:40
I request 2wap scholars on physics to solve this question n help me for answer. The question is based on gravitation chapter of 12th standard[MAHARASHTRA,INDIA ]:*... Thank you
I request 2wap scholars on physics to solve this question n help me for answer. The question is based on gravitation chapter of 12th standard[MAHARASHTRA,INDIA ]:*... Thank you
Eternal_Knight 2011/01/10 13:45
The question is
find the height of communication satellite.[given G=6.67*10raise to -11,Mas of earth=6*10raise to 24kg,radius of earth=6400km ]. Be kind enuf to attach the page on which u have solved. Or explain here. Thank you
The question is
find the height of communication satellite.[given G=6.67*10raise to -11,Mas of earth=6*10raise to 24kg,radius of earth=6400km ]. Be kind enuf to attach the page on which u have solved. Or explain here. Thank you
okay bro lol
i donno i am afraid of mathenatical solutions 
Insenus_AmoR 2011/01/16 19:36
For the communication satellite, T=24 hours = 86400sec. G and M are given, Substituting these values in the formula, we get
r^3=(T^2 * G * M)/ 4*pi^2
(86400^2) x6.67x10^-11 x 6 x 10^24/(4*(3.14^2))
r^3 = 7.542*10^22
r=42.25 *10^6 m
If h is the height of the satellite above the surface of the earth and R is the radius of the earth,
r = R + h
h = r-R
Now R = 6400 km = 6.4 x 10^6 m
h =r-R = 42.25 x 10^6 - 6.4x10^6 = 35.85 x 106 m
= 35850 kms
For the communication satellite, T=24 hours = 86400sec. G and M are given, Substituting these values in the formula, we get
r^3=(T^2 * G * M)/ 4*pi^2
(86400^2) x6.67x10^-11 x 6 x 10^24/(4*(3.14^2))
r^3 = 7.542*10^22
r=42.25 *10^6 m
If h is the height of the satellite above the surface of the earth and R is the radius of the earth,
r = R + h
h = r-R
Now R = 6400 km = 6.4 x 10^6 m
h =r-R = 42.25 x 10^6 - 6.4x10^6 = 35.85 x 106 m
= 35850 kms
EpIcInCoGnItO 2011/01/16 19:42
whats the hell?
whats the hell?Quote: AfaQue: For the communication satellite, T=24 hours = 86400sec. G and M are given, Substituting these values in the formula, we get
r^3=(T^2 * G * M)/ 4*pi^2
(86400^2) x6.67x10^-11 x 6 x 10^24/(4*(3.14^2))
r^3 = 7.542*10^22
r=42.25 *10^6 m
If h is the height of the satellite above the surface of the earth and R is the radius of the earth,
r = R + h
h = r-R
Now R = 6400 km = 6.4 x 10^6 m
h =r-R = 42.25 x 10^6 - 6.4x10^6 = 35.85 x 106 m
= 35850 kms
r^3=(T^2 * G * M)/ 4*pi^2
(86400^2) x6.67x10^-11 x 6 x 10^24/(4*(3.14^2))
r^3 = 7.542*10^22
r=42.25 *10^6 m
If h is the height of the satellite above the surface of the earth and R is the radius of the earth,
r = R + h
h = r-R
Now R = 6400 km = 6.4 x 10^6 m
h =r-R = 42.25 x 10^6 - 6.4x10^6 = 35.85 x 106 m
= 35850 kms
_dreamprince_ 2011/01/21 12:18
Quote: Ellainey: Wat would it help if give correct answer or not.
it wil help in -kicking u out of this earth .hehe.
Alok 2011/01/30 14:07
r=[GMT*T/4*9.86]rise to 1/3,
where T=24hours &sq of pi=9.86,,calculate then r=4.2*10000 km.,,and h=r-R,,then h=36000km.
r=[GMT*T/4*9.86]rise to 1/3,
where T=24hours &sq of pi=9.86,,calculate then r=4.2*10000 km.,,and h=r-R,,then h=36000km.
Ha ha ha
Replies: 22
#2 General Area
A forum for life in general. Post about news, social matters, relationships, lifestyle, or anything on your mind.